Recent content by misnoma

assume a level ground with no atmospheric resistance. time of flight for the first half (rising) is t = (v-u)/g = 0.666 sec, sot he time of flight for the last half descent is also 0.666 sec. Total time is thus 1.333 sec. with no reistance to motion in the x-axis the distance traveled is...

panthomjay is right. understand that the centripetal acceleration along the x-axis will be the resultant of the weight of the chair and the tension in the chain. when this ia at the required angle you will be able th calculate Fcentripetal and also tangential speed - do you know the mass...

whilst we are successful in colliding matter to identify yet further fundamental particles, and being aware there is a limit on speed due to mass end energy problems, and given that matter and mass are interchangeable, might it be possible to collide a single photon with another (this must rely...

simply put: the cooling compartment must be at the top - when slightly warmer air in the fridge rises (from foods or open door etc), it will come into contact with the cooling fins at the top. Here it will loose energy, become more dense (for a given volume) and consequently sink in the warmer...

:smile: :smile: :biggrin:

"In other words the force grows linearly as you move towards the surface." I picked up on this and made the assumption that it was moving towards the surface from the outside. (incorrect assumption). which is why I mentioned 1/d^2

Thanks fellow brit

Yes- inside - but not outside. was there some mis understanding here?

look up gravitational potential well and it should become clear.

F if proportional to 1/d^2

sorry I meant good not godd!

godd answer chronos. But for generality, the fact that the fridge magnet is on the fridge (steel door). This will act in the same way as a keeper. Hence it will maintain its magnetism for a substantial length of time. More than if it was just resting on a table for instance. Of course, the...

STOPPPPPPPPPPPPPPPPP: there is no paradox. Simply do the vector sum for all the masses involved with regards to their position. If the resultant of all forces is zero, then there will be no change in positin for any of the masses. If there is a change in position to satisfy equilibrium, then...