Recent content by MissBisson

ah right that makes sense so T3 is greater than T1+T2 Thank you for clarifying that :) your help is very much appreciated! i went to talk to my prof and there was a glitch in the system, my last post of answers was correct, the system wasnt reading the lower case letters. so the final...

Ohh alright i understand what you mean! however since the pulley is not moving it would be considered a system at equilibrium for that specific case, with a tension force on both sides of the pulley acting down and one acting up. so wouldn't that make T3 = T1+T2?

from the last combination i posted, is there anywhere else where i am wrong?

Thank you for clarifying the explanations! From what you have said it seems that it is on E) that i am wrong. when i consider the net force and acceleratin on the pulley, the vertical accelerations cancel out since the both masses are accelerating at the same magnitude but in opposite...

A) T2 is greater than T1 since the pulley needs a bigger torque to rotate in that direction B) m1g is less than T1. T1 = m1g + ma hence T1 is greater C) m1g + m2g + mpg is greater than T3 D) true since the whole system is accelerating evern the pulley E) T1 +T2 is less than T3 because T3 holds...

Based on (m1+m2+mp)g - T3, T3 would be equal to (m1+m2+mp)g. but i don't understand what you mean by m1=mp=0 :S

It is accelerating in the counterclockwise direction making m2 go down and m1 go up so the negative direction..?

But how does the acceleration of the mass affect T3? T3 just holds up the whole system so isn't T3 just related to the mass of the system and not the acceleration?

Homework Statement A pulley with mass Mp and a radius Rp is attached to the ceiling, in a gravity field of 9.81 m/s2 and rotates with no friction about its pivot. Mass M2 is larger than mass m1. The quantities Tn and gare magnitudes. Homework Equations (Select T-True, F-False, G-Greater than...

When I did Torque = (T1-T2)R = I x (a/R) It worked out perfectly :) thank you

Homework Statement A 27.1 kg block (m1) is on a horizontal surface, connected to a 6.70 kg block (m2) by a massless string as shown in the figure below. The frictionless pulley has a radius R = 0.097 m and a moment of inertia I=0.070 kgm2. A force F = 213.7 N acts on m1 at an angle theta =...

Yes it was 1.67m

Yes i do thank you very much :)

Thank you so much! it finally worked :)

The is the equation i have: U(xf) = 3(xf)^2 +4(xf) -5 , do i have to set it equal to the initial potential energy which was 2 ? or do i have to somehow include the kinetic energy in the equatin also?