Recent content by mistalopez

That was my question. How am I suppose to solve for 3 unknowns when I cannot cancel anything out. I need atleast 2 known variables to solve any of the equations. Do I subtract equations or some sort of method?

But now I am stuck because I can only get one value. A+B=1 => A=1+B -4A+2B+C=-7 => 5A+2C=16 =>

I realize there is a mistake, but you could please elaborate upon my mistake without giving me the answer? Your response did not make it obvious or clear for me. Maybe a more indepth response would help me better understand my own mistake. Thank you in advance for taking the time to help me...

Homework Statement Write the partial fraction decomposition of the rational expression. Check your result algebraically. (x2 – 7x + 16)/[(x + 2)(x2 – 4x + 5)] The Attempt at a Solution [A/(x+2)] + [(Bx+C)/(x2-4x+5)] x2-7x+16= A(X2-4x+5)+(Bx+C)(x+2)...

Homework Statement Write the slope intercept forms of the equation of the lines through the given point (a) parallel to the given line and (b) perpendicular to the given line. Point: (2,1) Line: 4x-2y=3 Homework Equations y-y1=m(x-x1) y=mx+b The Attempt at a Solution I...

I got 6x-6-6x-6h-1 = -6h-7 The final answer -6h-7/h(x+h-1)(x-1) Is that correct?

Homework Statement See attachment! 2. The attempt at a solution I multiplied by the LCD of (x+h-1)(x-1) and got 6h/h(x+h-1)(x-1) . I then got 6h/h^2+2hx-2h . However, my answer seems to be wrong. What is my error?

Homework Statement (x-7)^2=(x+3)^2 2. The attempt at a solution I squared both sides and received x-7=x+3 However, that cannot be correct because the variables cancel out which means there is no solution. The book shows that there is a solution of 2

Homework Statement (1/x-3)+(1/x+3)=(10/x²-9) 2. The attempt at a solution (1/x-3)+(1/x+3)=(10/x²-9) (1/x-3)+(1/x+3)=(10/(x+3)(x-3)) - I factored the x^2-9 to make it easier to multiply by LCD. x+3+x-3=10 - I multipled both sides by the LCD [(x+3)(x-3)] 2x=10 - Combined like...

Sorry for the long time to reply. I tend to over complicate math problems and logic problems and then smack myself later for it was staring me in the face. I used the Pythagoras' theorem and got 1.9cm/sec for the hypotenuse. Thanks again and problem solved.

Correct, that is the definition of displacement. Knowing that it is a rectangle, I tried to use a slope knowing it went 27m to the right and then 21 m down. I got 27m/-21m as the slope and then simplified I got -9/7. However, when I plug it into the average velocity equation, it does not come...

Yes, positions A and B on the pool are opposite corners. The answer to (b) 1.9cm/s is NOT a given. I looked it up in the back of the book to determine if I was correct. I do not understand the steps to finding the displacement to use in the average velocity equation (if that is the correct...

Homework Statement An insect crawls along the edge of a rectangular swimming pool of length 27 m and width 21 m. If it crawls from corner A to corner B in 30 minutes, (a) what is the average speed, and (b) what is the magnitude of its average velocity?Homework Equations average speed =...

Thanks for such a quick reply and the warm welcome! However, the answer flew way above my head. Would it be possible to explain it in more depth for someone who does not have much experience in physics to understand?

Homework Statement The general equation for a parabola is y=ax²+bx+c, where a, b, c are constants. What are the units of each constant? Homework Equations y=ax²+bx+c The Attempt at a Solution The answer is a: 1/m; b: dimensionless; c: m How exactly did they get that answer in the book...