Ok I'm going to take another shot at this one.
stress = load/area
therefore stress = 30,000/.5
so the tension stress is 60,000 psi
Am I correct in that the maximum shear stress is equal to one-half of the maximum tensile stress which would make the shear stress 30,000 psi?
If I'm right this...
Thank you for your help. I think I am understanding now.
Stress=force/area
therefore stress = 50,000/.25
so the stress is 200,000 psi
then using Hooke's law..
strain equals stress divided by modulus of elasticity
therefore strain equals 200,000/30,000,000
so strain is .0066667
then to find...
Thank you for the warm welcome.
I think the fomula needed to find elongation is:
Axial tension strain equals change in length divided by original length
I know that the original length is 100 ft, but I still need to find the stain in order to complete the problem.
I think this...
Hi. I am hoping someone can be of assistance in helping me solve a problem.
I am trying to calculate the longitudinal elongation of the steel bar shown in the attachment. I don't know where to start, so if anyone could point me in the right direction such as which formula I should use I would...
Does this mean that I can use any variable for length of the cross section since I am not specifically given one?
Such as if I used 12in for the length I could determine the area of the object would be (12x2) + (12x2) + (.25x12) + (.25x12) = 54 sqin
Which would then be used in the formula...
Hello, I am hoping that someone can help to point me in the right direction to solving the following problem.
I need to find the max tension stress and max shear stress of the object shown in the attachment and then compare those stresses with the ultimate tension stress of 64,000 psi and...