Recent content by Mo

Hello, i am trying to understand the concept of active /reactive /complex power and am having some trouble understanding how the reactive powere 'oscillates back and forth between inductor and source'. Ok, let's say i have a pure inductive load, i know that the power consumed is 0, and i...

Yes, that's true. So now i have worked out the value of surface area for half of the triangle and found that to be (pi.root3.a^2)/4 For the whole triangle, this value ahs to be multiplied by 2 surely?. Therefore final answer = (pi.root3.a^2)/2 The thing is, the answer i got given for this...

Homework Statement Determine the surface area and volume of a solid formed by rotating an equilateral triangle of side a about its base. Homework Equations The Attempt at a Solution ----------working out surface area-------- Integral of 2.pi.y dx with limits of a and 0. I...

Homework Statement Question attatched in image file.Homework Equations The Attempt at a Solution A1.b) Input will be a sine wave 6Vpp . When the input goes positive, D1 conducts and short circuits the ‘first’ resistor. D2 doesn’t conduct (it acts as an open circuit) and so Vout = voltage...

Thanks for the link and all your help. :approve: Good night.

First of all, thanks for your help so far, secondly ... how would I go about tackling those next two parts of the question! It's mainly a case of getting the boolean expression into the correct form. (which I am lost in!) Regards, Mo

In that case i think it would be possible to, applying de Morgan's laws, split up this 4 input NOR gate into two, 2 input NOR gates AND 'ed together. NOT (A + B) . NOT (C + D) The output of this would be equal to the 4 input NOR gate. Regards.

We would have 4 input A B C D. We have a connection from both C and D to an AND gate (which is the CD part) We also have a connection from all A B C D to a NOR gate. (which is the NOT A+B+C+D part) Output from these two gates are then connected to an OR gate.

de Morgan's laws tell us how an AND can be converted to an OR. Not (A.B.C) = NotA + NotB + NotC Not (A+B+C) = NotA. NotB. NotC e.g : Not A+B = NotA . NotB For the first part i got: CD + Not(A+B+C+D) To get this i combined some of the expressions, then finally used demorgan's law...

Homework Statement Please see the attatched picture. Homework Equations The Attempt at a Solution I can complete the first part of the question, but i am not sure how i should do the second part. I would be grateful for a quick explanation or tutorial in how to do this...

Thanks for your help all. :smile:

The capacitor will discharge and then recharge on the negative input wave, so on and so forth. Essentially the output as seen from the load will be a DC voltage (almost a Dc voltage - as far as i know this will depend on how well the output is smoothed) The output DC voltage will be the input...

Homework Statement What is the name given to this type of circuit? Sketch output voltage waveform for a sine wave input across nodes A-B. Homework Equations Please see attachment for circuit. The Attempt at a Solution Well I am inclined to say it is a full wave rectifier with a...

Thank you very much indeed! I do not think I would have got that in a loooong time! Thanks for the link as well. Regards, Mo.

Homework Statement integrate with respect to x Homework Equations integral of cos x / (2 - cos x) dx The Attempt at a Solution I attempted to use the substitution of tan (x/2) but got lost in it. I don't think it was correct to subsititute t = tan(x/2) because it was not in...