1. The problem statement, all variables and given/known data Question attatched in image file. 2. Relevant equations 3. The attempt at a solution A1.b) Input will be a sine wave 6Vpp . When the input goes positive, D1 conducts and short circuits the ‘first’ resistor. D2 doesn’t conduct (it acts as an open circuit) and so Vout = voltage across R in parallel = 3V. When the input goes negative D1 doesn’t conduct and D2 does. Therefore, the voltage goes through the ‘first’ resistor but the second resistor in parallel is short circuited. Therefore Vout = 0v since the diode is ideal. A1.C) The output from the op-amp will be = to vin . -1 (negative feedback) .When vin goes positive, D conducts and Vout = -0.7V When Vin goes negative D acts as an open circuit, so the Vout = 1.5V ------------------- Obviously the answers above somewhat incomplete since a graph of v_in/v_out is also needed, but i just wanted someone to check if i have got the right idea. regards, Mo.