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Centripetal Acceleration of a satellite above a planet of the Earth's radius.
Thanks for help. It has come to me now. 9.81 = v^2/6400000 So v = 7.9e3 ms-1 and so time for 1 orbit is (2pi)r/v- mogsplanet
- Post #5
- Forum: Introductory Physics Homework Help
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Centripetal Acceleration of a satellite above a planet of the Earth's radius.
The question has no mention of mass so this should not be used. All the information I have is in the original question. It is A satellite in low orbit around a planet with same radius as the Earth.- mogsplanet
- Post #4
- Forum: Introductory Physics Homework Help
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Centripetal Acceleration of a satellite above a planet of the Earth's radius.
Homework Statement A satellite is in orbit just above the surface of a spherical planet which has the same radius as Earth and the same acceleration of free fall at it's surface. Calculate: i) Speed ii) Time for 1 complete orbit. Radius of Earth = 6400km or 6400000m and accel. of free...- mogsplanet
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- Acceleration Centripetal Centripetal acceleration Planet Radius Satellite
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- Forum: Introductory Physics Homework Help