Recent content by monkeysmine

  1. M

    Torque of a uniform rod being pivoted.

    Yeah, I meant my original thought was cos(theta) for some reason I kept writing sin. It was probably just kind of late. Apparently Webassign demanded that we round and truncate making the answer 4cos(theta) (shady if you ask me) but hey.
  2. M

    Torque of a uniform rod being pivoted.

    ...Okay sorry I don't know what I was thinking yesterday I meant I tried cos(theta) and cos(90-theta)...
  3. M

    Torque of a uniform rod being pivoted.

    3.773 = .5 * 1.1 * .7 * 9.8, so actually, I don't understand why you are saying my answers are incorrect.
  4. M

    Torque of a uniform rod being pivoted.

    I got T = 3.8cos(90-theta) as a replacement to 3.9sin(theta). I just used my last "guesses" on this problem though, so I will talk to my teacher tomorrow about it. I am positive that one of my 50 answers were right (30+ variations on rounding and truncating) of 3.773cos(90-theta) and I also...
  5. M

    Torque of a uniform rod being pivoted.

    Well I double checked my work on a calculator and I'm positive that my cross product was right. I did realize that an error I made was that R is actually r/2 since r goes from the pivot to the center of mass, but this still does not give me the correct answer.
  6. M

    Torque of a uniform rod being pivoted.

    I only tried 2) because 1) did not work. I crossed .5Lcos(theta)i - .5Lsin(theta)j + 0k with 0i -mgj + 0k
  7. M

    Torque of a uniform rod being pivoted.

    Homework Statement A uniform rod 1.1 m long with mass 0.7 kg is pivoted at one end, as shown in Fig. 9-46, and released from a horizontal position. Find the torque about the pivot exerted by the force of gravity as a function of the angle that the rod makes with the horizontal direction. (Use...
  8. M

    Determination of % Comp of Al/Zn Alloy

    Oh! Whoops my bad! Thanks so much for your help, by the way! Much Appreciated :D
  9. M

    Determination of % Comp of Al/Zn Alloy

    Um which details are faulty?
  10. M

    Determination of % Comp of Al/Zn Alloy

    Ah.. the five-day weekend has completely crippled my brain :( I think I meant .00545, which is the moles of hydrogen produced from PV=nRT (762mmhg)(.1315L)/(62.4mmhg*L/moles*K)(294.4K). I obtained .1315L as the amount of H2 produced, since volume water displaced = volume h2 produced...
  11. M

    Determination of % Comp of Al/Zn Alloy

    Ummm... Would (.1229-x gZn)(1mol/65.4gZn)(1/1) = 4.54 (x gAl)(1mol/27.0gAl)(3/2) = 4.54 be the right equations?
  12. M

    Determination of % Comp of Al/Zn Alloy

    Zn + HCl -> ZnCl2 + H2 Al + HCl -> AlCl3 + H2 if all I can think of..? But I don't know how to calculate the amount of hydrogen produced. I know the hydrochloric must be the limiting reagent, to ensure complete reaction, but further than that, I'm stumped.
  13. M

    Determination of % Comp of Al/Zn Alloy

    Homework Statement The purpose of the lab is to determine the % comp of an alloy from the volume of hydrogen that is produced in the reaction. We did a lab, in which an alloy was reacted with hydrochloric acid, in a test tube with a stopper and tube leading to a 500ml sidearm flask, with a...
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