Recent content by moooocow

Well, that would be why it isn't working, I am not really sure how to go about it, besides the kinetic energy, but I am not sure exactly how that would work with it just rolling horizontally.

F basically splits up and connects on both sides of the roller in the center of the end caps. At first I thought you could use torque to find the angular acceleration and use that to find the center of mass acceleration but my answers are not coming up correct.

And if anyone could help with this one I would be forever in debt to you, hehe. A constant horizontal force is applied to a lawn roller in the form of a uniform solid cylinder of raidus R and mass M. Show that the acceleration of the center of mass is 2F/3m. the minimum coefficient of...

Two blocks are connected by a string of negligible mass passing over a pulley of radius .250m and moment of inertia I. The block on the frictionless incline(it has a picture of incline with block 1 on it at theta = 37, and block 2 is hanging off the side by the pulley) is moving up with a...

A car traveling on a flat circular track accelerates uniformly from rest with a tangential acceleration of 1.7m/s^2. The car makes it one quarter of a way around the circle before it skids off the track, Determine the coeficient of static friction between the car and track? I really have no...

Well, if you take that as an infinite path than anything that starts and ends in the same place would be infinite, this would include say a square, just pointing out the obvious though, so please ignore me

So the force on the individual pieces, and the object as a whole would just be the applied force to the x plane and the gravitational force to the x plane? a = F + mg sin(Theta) / m Thank you very much for the help, I have no idea why I was having so much trouble.

I am just really confused on this one, is it not needed to take the force in the "x" direction because since the acceleration and force are on the same "line", which we could use as the "x" axis? When finding the tension I had, for one example, m4*a = F cos(theta) - T3 cos(theta) and this was...

It is almost time for the end of term exam and I am looking over my old exams and am confused by one problem. Masses m1,m2,m3,m4 are cnnected together(by a "string") on an incline theta = 22 degrees. m1 and tension = T1(connects m1 and m2) start nearest the bottem of the ramp, and a force F =...

Thanks a lot, I am still having a problem understanding why exactly the chain rule is used. on the left side all you had to do was take the derivative of V and the derivative of t. I understand that \frac{dr}{dt} is what I am trying to find, but I don't understand the reasoning behind why the...

Ok, In my calc book I am having problem with the first example they give in a chapter on Differentiation. It gives the equation of V = \frac{4}{3} \pi r^3 and then it is differentiated by time = t. \frac{dV}{dt} = \frac {dV}{dr} \frac{dr}{dt} = 4 \pi r^2 \frac {dr}{dt} I don't quite...

I don't think this is homework but if it is sorry for putting it in the wrong spot. Ok, I was out of physics class for a few days due to a sinus infection, I REALLY did not want to miss it but sometimes its just not an option. I read the book while I was out to try and keep up but my book...