Recent content by Morphayne

But when I solve cos(53.1) = v/10 for v I get: v = 10 cos(53.1) v = 0.6km/h Then: Time = distance/velocity Velocity = 0.6km/h Distance = 120m = 0.12km So; Time = 0.12/0.6 Time = 0.20 min The correct answer is 0.9 min. Maybe a picture will help. Sorry if I'm asking too much, I'm just...

Homework Statement I'm having trouble with a word problem involving the parallelogram law of vector addition. The problem reads as follows: Two forces with magnitudes 8N and 11N act on a large object. The angle between the forces is 30 degrees. a) Draw a diagram to represent the combined...

Homework Statement I'm not sure if I posted this in the right section, I apologize If I did anything wrong. I am stuck on part 15(b), so I just wrote my answer down for the parts I got right because I felt that it is relevant information. I posted question 14 because question 15 is just an...

To get the y-coordinate, I must sub. x = 1/e into y = ln x. Finally, to get the equation of the tangent I would use y = m(x-p)+q and sub. in the appropriate values. Right? Did I get the part with the derivative right?

So; y = ln x y' = 1/x The derivative equation gives us the slope of any tangent, at any point along the given function. What do I do from here? Should I sub. y' = e? y' = 1/x e = 1/x xe = 1 x = 1/e ?

I don't know how to solve it: y = ln x -sub. y = e: e = ln x Now, here is where I'm stuck. I solve for x right? But how do I do that?

But I don't have any x,y coordinates. If I did, I wouldn't be stuck.

I don't understand.:confused: Do I take the answer of y=ln e and plug it into y=ln x? If so how would I solve for x? Can someone please help me with a solution? I have an exam in 4 hours and there will be at least 3 questions like this worth(all together) 30 marks out of a possible...

Well I just wrote y=xe as my answer but when I checked my answer it was wrong. I'm guessing that I need to do something using the derivative of y=ln x, but that is as far as know. I'm pretty weak with all this work involving Euler's constant.

Help my guys. I'm so hopelessly lost on this question... Problem: Determine the equation of the tangent to the graph of y=ln x that has slope e. The answer in the book is y=ex-2. Please help. :smile:

I need help differentiating this equation: y=(x-1)^2(6^x) What I have (I went wrong somewhere): dy/dx = (x-1)[(x-1)(6^x)] =(x-1)[6^x(1+ x ln6 - ln6) =(x-1)6^x(1+ x ln6 - ln6) So; My final answer: (x-1)6^x(1+ x ln6 - ln6) Answer in the textbook...

Well, the answer in the textbook is says that there is a horizontal asymptote at y=0 which means that this limit somehow equals zero... Help please!

Hi. I'm confused about calculating the limit of a function involving Euler's number. I need to know the proper way to find the limit so I can determine the equation of the horizontal asymptote of the function. I do know, in my head what the graph looks like so I know that there is a...