Recent content by motoxtremechick

haha oooo man ok wow so now to figure out the closest..?? it wouldn't be the 25 meters would it?

it couldn't have happened?

so a=.5 b=-6 c=25 you can't have a - square root right wouldnt those values give you a negative under the root sign?

wait i think i switched my values so i got 3.27 and -15.27

i got t=-.064 and t=.3054 ?

my mistake there is still supposed to be a unit..i just did that to get rid of the one t and make the other one just t instead of t^2 then if i move everything it will be... thats where I am stuck t=12s-25m

k so kinematics equations set equal..have to solve.. .5m/s^2(t^2)=6m/s(t)-25m so i divided all by t to get .5m/s^2(t)=6m/s-25 ...?

well 0m/s(t)+0.5(1.0m/s^2)(t^2)=6m/s(t)+0.5(0m/s^2)(t^2)-25 then by taking out the ones that would equal 0 out i reduced it to.. .5m/s^2(t^2)=6m/s(t)-25 hmm

ooo rigght..geez hmm well i am very horrible at this i don't know how to get t out of the equation effectively to solve for it.. would i just divide both sides by t^2 then...no see i am just digging a deeper hole with this problem

Thank you for bearing with me [=! so just to get to the 25 meter mark from 0 the pedestrian would have to run 150 seconds... wait so i did d+25=Vf^2-Vi^2/2a? so d+25=18m d=-7 so he is 7m away from the bus? so 25 plus the extra 7 the bus travles so he is 32m away from the bus?

o alright. thank you im sorry I am just way lost and i guess not thinking straight the only equations i have are the kinematics equations and i can't think of which one to apply that uses what i have/dont have

right right my bad on the A and V mess ups sorry. and then would i use the d=Vf^2-Vi^2/2a to find a of the pedestrian? putting 25m into d?

ok so BUS V=1.0m/s^2 PED a=6.0m/s d=25m could i possibly use d=Vave(t) to find time and use 25 meters as distance or is that wrong?..

A pedestrian is running at his maximum speed of 6.0 m/s to catch a bus stopped by a traffic light. When he is 25 meters from the bus, the light changes and the bus accelerates uniformly at 1.0 m/s2. Find either {A} how far he has to run to catch the bus or {B} his frustration distance (closest...

two ropes are attatched to a heavy object. the ropes are given to two strong people with instructions for each to pull with 1000N of force. what is the total resultant force if the two women pull.. in the same direction_________F=2000N in opposite direction__________F=0N at right angles...