Recent content by Mr Real

Okay, now I am clear with this. Thanks, for clearing my doubts again! :oldsmile: Mr R

But you had used this example as an analogy to help me understand that if we have an equality (C) = (F)(G), and we multiply this equality by an elementary matrix E on both sides to get an equivalent equality, then in the RHS, we'll get (E)(F)(G) and we'll evaluate it as (EF)(G); so, considering...

@Stephen Tashi, sorry to bother you but I had a doubt regarding this. You said here that in the equation 0 = (x/7 - 1/7)(x - 2), if we want to convert this equation to an equivalent equation by multiplying both sides by 7, then in the RHS we are only allowed to multiply the factor (x/7 - 1/7) by...

Thank you @Borek and @snorkack for clearing my doubts. :oldsmile: Mr R

Sorry, Borek if I came across that way. I am not deliberately trying to waste your time by behaving stupidly, I am genuinely not clear with the things I asked. jim mcnamara, I do recognise Borek's helping attitude and patience in trying to clear my doubts, and because of that most of my doubts...

Borek, can you please answer my doubt? Was I right when I said in post #87 that the 2 vapor pressures can become equal only if the decrease in vapor pressure is less for the solution (brine in our case) than for the solid state of the solvent (ice in our case)? And if I was right then does this...

Sorry, but I didn't know that and it was kind of a minute detail in the graph. You asked me to follow the plot, so I did and listed all my observations. I have understood the important part.

Yeah, I can see that but I was talking about the absolute value of the difference in vapor pressures. Okay, I didn't notice that, I thought the minimum was at 273 K in the plot. Yes, I agree it doesn't grow initially. Well, I've been talking about the absolute value for all this time. The...

Yes, I can see that but What I meant is this: If we start from 273K and go to lower temperatures like 272 K, 270 K, etc. Tthe difference in vapor pressure is becoming larger and larger. And similarly if we start from 273 K and go up to higher temperatures, like 275 K, 276 K etc. the difference...

No, I'm not misreading the plot and I know that the temperature scale is in K.(Besides, there is no point marked as 0 in the graph, so how can I get confused about it ) Well, I think what I wrote is true. Maybe I didn't put clearly what I mean there. I mean that from the graph we can see that if...

The difference between the pressures goes up as we move from 0°C to lower/upper temperatures.

Okay, I've written all my conclusions: From the graph, I see that after 0°C, the decrease in v.p. of the 1M glucose solution curve is lower than that for the sublimation curve. Also the curve for sublimation is steeper than the curve for glucose. I also get the following conclusions(I don't...

So, is it true for all solvents? I think it is because ΔHsub is always greater than ΔHvap(or is it not?). So, the sublimation curve will always be steeper than the vaporization curve. What I'm asking is this: I don't think the vapor pressures can become equal if the decrease in vapor pressure...

Oh, analysing the graph more carefully, I see that the decrease in vapor pressure is less for glucose solution than for the solid state for the same decrease in temperature, so I was right earlier when I said that the decrease in vapor pressure will be less for the brine than that for the ice...

*I'll pretend that the we're still talking about brine rather than glucose, as I feel more comfortable about it* From this graph, I see that the curve for the ice is steeper than the curve for brine, that means before the melting point is reached, the decrease in vapor pressure is more for the...