Recent content by Mrcelloman99

  1. M

    Twin lead Tx line radiation losses

    Hi all I understand that at high frequencies, a twin lead Tx line has high radiation losses because the conductor separation becomes close to the wavelength size, allowing the conductors to act as antennas. Can one still be used to transfer a high frequency signal a short distance from an...
  2. M

    Question about simple schottky diode mixers

    Oh yeah, and I can't find VCos nearly stable enough to act as finely-tuned LO's so that's probably a no-go.
  3. M

    Question about simple schottky diode mixers

    I appreciate your replies. I'm trying to build a speedometer for skis and longboards and the like that charts a user's speed by sending off off a signal and determining the velocity by reading the doppler-shifted return signal, like a radar gun only on a much smaller scale. I have a sensor...
  4. M

    Question about simple schottky diode mixers

    I see, I wasn't accounting for negative harmonics. Well I'd rather not use a quadrature mixer if I don't have to, but it depends. See the actual frequency I am trying to oscillate will be fed into a frequency counter of some type and information will be extracted from it. Will the -3 kHz image...
  5. M

    Question about simple schottky diode mixers

    meBigGuy: Thanks for the insight; I'll consider your suggestion.
  6. M

    Question about simple schottky diode mixers

    I don't think I was specific enough. The entire setup would be composed of my ~10 GHz signal (which has already been received through a close range transmission from another circuit), the diode, and a 10GHz VCO. The intermediate frequency would be from DC to 3 kHz. The filter would then be...
  7. M

    Question about simple schottky diode mixers

    I am new to mixer circuit design, but I need to build a simple mixer that will downconvert a 10 GHz signal to a DC to 3 kHz signal. I know I can do this with a schottky diode and lowpass filter to isolate the lower harmonic (f-IF = f-RF - f-LO). The problem is that the RF signal will be in the...
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