Hammertime, I guess for atoms and "macroscopic" objects like molecules yes, but for a big macroscopic object like a key we are very very far. It seems that for increasing complexity of the object the number of resources used scales exponentially. Even if there is a way, maybe it is too costly.
Oh man, I didnt think you would go this far XD.
I have thought before in a kind of paradox with observers going away from each other at light-speed. With a third observer, the one in which the detections are simultaneous, you have some quantitative surprises...
You can't tell which one...
You quantum system gives your Hilbert-space. That teleportation couples with subset of Hilbert-space... in terms of photons I think you teleport the full quantum state. If you can prepare a two-mode squeezes vacuum state and perform the bell-measurements, you teleport whichever state you want...
The quantum state of Alice has changed after Bob's measurement. So, its physical properties, like spin, have changed. Alice can't determine this alone, but the change occurred. If Bob say to her his outcome, she knows that her state changed. And it was not the communication that changed the...
When you teleport the full quantum state it will have all the properties of the original one. And that is the gain in teleportation: you don't need to know which one is your state, you know that after the protocol the state in the other side will be your state. So you don't need to reconstruct...
Yep, we would end going into the definition of what a quantum state is, or what an actual atom is*.
However, the teleportation scheme in any case is the teleportation of the quantum state, which possesses all the relevant physical properties of the atom.
(* it is hard for me to accept this...
With a single photon she can't say anything. This is an important point. She can't tell if Bob obtained + or - in his measurement, unless Bob tells her his outcome.
But there is the influence, since repeating the experiment many times you observe a statistical deviation (Bell-inequality...
The properties are the same, since is the same quantum state. They teleported the state of the atom. There is not a difference between atom and quantum state of the atom. The state - wave function/density matrix - has all physical properties of the atom encoded. In this sense they indeed...
Nope, any experiment that observes the violation of a Bell-inequality precisely verifies the "spooky" influence of one particle into another.
But I can describe one for you. If you take the spin-singlet state (maximally entangled), initially the local states (Alice and Bob states) are...
Sorry:
http://futureblast.com/2011/04/first-teleportation-with-atoms/
This second one maybe is also an experiment on this, but I am not so sure:
http://www.nature.com/nature/journal/v396/n6706/full/396052a0.html
I am not a fan of NMR.
Hello, Dr Chinese, thanks!
I don't understand the word...
[i]As for my taste, two objects are independent if whatever happens to one of them has no influence on other. If we agree for that definition, entangled particles are independent.[\i]
If we agree in this definition, entangled particles are dependent. A measurement in one side changes the...
No, local deterministic operations - operations in one part - don't affect the state of the other part. Only the probabilistic act of measurement can affect the second particle state (description).
The force you are saying would be translated as a local quantum evolution - represented as a...
There is no need to scan the hole object. That is the point of quantum teleportation, you send your unknown quantum state to another person and the person is sure that is your state (with high fidelity).
However, you and your partner need to share a quantum channel - i.e, a quantum entangled...