Recent content by mrmonkah

Homework Statement A house is heated by means of a carnot engine operating in reverse (Heat Pump). The outside Temperature (Tc) is 270k, and the required inside temperature (Th) is 300k. If heating the house to this temperature normally requires 10kW of electrical heating, how much power is...

Im studying Classical Physics and currently covering resonance, one question i got thinking about was why we rattle things that are stuck. Am i right in thinking that we apply a resonance to the natural frequency of the stuck object in order to magnify it's amplitude and hence give our selves...

Homework Statement A mechanical oscillator system is driven sinusoidally with a force amplitude, F(max). The Oscillator resonates at 27Hz. When driven with the same F(max) at 26Hz or 28Hz, the resulting oscillation has half the amplitude as at resonance. When F(max) is instead applied...

Damn, every time. A habit i need to get used to.

Homework Statement Solve the following: \frac{dy}{dx} = \frac{1 + y}{1 + x} Homework Equations Fundamental theorem of calculus - thanks gabbagabbahey The Attempt at a Solution Re-arranging to get y terms and x terms on opposite sides: \int\frac{dy}{1 + y} = \int\frac{dx}{1 +...

Oh i see now. So with questions like these, i should generally keep all the y's on one side and the x's on the other? Ill attempt another question and post it to see if i have my head in the right place. Thank you Char.Limit, and as ever, you make a good point.

Ahh okay fair enough Char.Limit, i am confused as to why re-arranging the initial equation (as i did earlier) yields such a different result?

Ok, so if i integrate both sides i get: \frac{x^{2}}{2} = \frac{y^{3}}{3} and y = \sqrt[3]{\frac{3x^{2}}{2}} Surely this isn't right is it? I don't recall coming across cubic roots in 'this particular' module. (I am simply looking for familiarity with the rest of the course)

Right, so carrying on from my first post, if i rearrange for y, i get: y = \sqrt{\frac{x^{2}}{2}}

Okay, more or less fixed now... thanks again Gabb

Hi gabbagabbahey, Sorry, i am just getting to grips with the funky math features on the site, so my translation from paper to web isn't vry good. First of all i put in a monster mistake on the web, working on correcting this now.

Homework Statement Solve the following: xdx = y^{2}dy Homework Equations Fundamental theorem of calculus - thanks gabbagabbaheyThe Attempt at a Solution \frac{dy}{dx}=\frac{x}{y^{2}} \int\frac{dy}{dx} = \int\frac{x}{y^{2}} =\frac{x^{2}}{2y^{2}} So with the question, I've integrated both...

Hi Redbelly, Ive submitted the work now. Unfortunately before seeing this post. I actually converted my units to SI. And so used: R = 8.314J/(K mol) Ive had some feed back in the past about sticking with the given units in some situations and not in others... and so i don't always head in the...

Homework Statement 100 moles of very dilute He gas are taken through the cycly ABC, where BC is an isothermal process. If P(a) = P(c) = 1atm, P(b) = 2atm and V(a) = V(b) = 3m^3, Calculate T(a), T(b) and V(c) Homework Equations eq1. PV = nRT eq2. V = nRT/P The Attempt at a Solution...

okay, i think i have the solution now, find power density, (power/surface area), Also Power Density = Mag of poynting Vector That is 'Power Density = \frac{E^{2}}{c\mu_{0}} Re-arranging for <E> for E-field. To find B-Field, use <B> = (1/c)<E>