ahh, i see what i did wrong. since vBx will be traveling in a negative direction, although it gives the same answer, my workings were wrong, which in this case are important. thank you
yes i did read your comments, and i did implement the corrections (except i missed out the (-) for vAx = 80)
i do apologize for making multiple threads, i just thought i'd post both questions together, as i wanted a check for one of my other questions...
if someone could check my answers to see if they are correct please this would help a lot, on the other hand, if they aren't, then advice would be greatly appreciated.
http://i21.photobucket.com/albums/b283/NMchugh/Various/veloctianswer.png...
my friend seems to think this is a check i can do to see if my answer is correct (gives the correct angle)
does this answer mean my workings are wrong?
tan∅ = vABy = 43.3 = 0.41, ∅ = tanˉ¹ ( 0.41) =22.4
vABx 105
i would greatly appreciate any help towards this...i thought my workings were correct, but i don't think they are now...
http://i21.photobucket.com/albums/b283/NMchugh/Various/velocity.png Question
vAx = 80 vAy = 0 vBx = 50 cos(60 vBy = 50 sin(60
First we look at the horizontal...