Recent content by Mrnickles

ahh, i see what i did wrong. since vBx will be traveling in a negative direction, although it gives the same answer, my workings were wrong, which in this case are important. thank you

yes i did read your comments, and i did implement the corrections (except i missed out the (-) for vAx = 80) i do apologize for making multiple threads, i just thought i'd post both questions together, as i wanted a check for one of my other questions...

if someone could check my answers to see if they are correct please this would help a lot, on the other hand, if they aren't, then advice would be greatly appreciated. http://i21.photobucket.com/albums/b283/NMchugh/Various/veloctianswer.png...

my friend seems to think this is a check i can do to see if my answer is correct (gives the correct angle) does this answer mean my workings are wrong? tan∅ = vABy = 43.3 = 0.41, ∅ = tanˉ¹ ( 0.41) =22.4 vABx 105

i would greatly appreciate any help towards this...i thought my workings were correct, but i don't think they are now... http://i21.photobucket.com/albums/b283/NMchugh/Various/velocity.png Question vAx = 80 vAy = 0 vBx = 50 cos(60 vBy = 50 sin(60 First we look at the horizontal...