- 5

- 0

http://i21.photobucket.com/albums/b283/NMchugh/Various/velocity.png Question

vAx = 80 vAy = 0 vBx = 50 cos(60 vBy = 50 sin(60

First we look at the horizontal X- component

vBAx = vBx - vAx

vBAx = (50 cos60) - (+80)

vBAx = 25 - 80 = -55km/h

Next we look at the vertical y- component

vBAy = vBy - vAy

vBAy = (50 sin60) - (0)

vBAy = 43.3km/h

vBA = √(vBAx)² + (vBAy)² = √(-55)² + (43.3)² = 70