- #1
Mrnickles
- 5
- 0
i would greatly appreciate any help towards this...i thought my workings were correct, but i don't think they are now...
http://i21.photobucket.com/albums/b283/NMchugh/Various/velocity.png Question
vAx = 80 vAy = 0 vBx = 50 cos(60 vBy = 50 sin(60
First we look at the horizontal X- component
vBAx = vBx - vAx
vBAx = (50 cos60) - (+80)
vBAx = 25 - 80 = -55km/h
Next we look at the vertical y- component
vBAy = vBy - vAy
vBAy = (50 sin60) - (0)
vBAy = 43.3km/h
vBA = √(vBAx)² + (vBAy)² = √(-55)² + (43.3)² = 70
http://i21.photobucket.com/albums/b283/NMchugh/Various/velocity.png Question
vAx = 80 vAy = 0 vBx = 50 cos(60 vBy = 50 sin(60
First we look at the horizontal X- component
vBAx = vBx - vAx
vBAx = (50 cos60) - (+80)
vBAx = 25 - 80 = -55km/h
Next we look at the vertical y- component
vBAy = vBy - vAy
vBAy = (50 sin60) - (0)
vBAy = 43.3km/h
vBA = √(vBAx)² + (vBAy)² = √(-55)² + (43.3)² = 70