Recent content by mst_ab

? y'=v=>(dy/dx)=v * y''=dv/dx=(dv/dx)(dy/dx)=v(dv/dy) =_*_=> y"=v(dv/dy)

a&b are constant, i found the way of solving this !: v=y' => y''=v(dv/dy) after solving, i get this equation: y'^2=(-0.82b*cosy-0.9b*siny)/1.36 (a=0.3) I'm not noob! I'm professor of university! please help me to solve this!: y'^2=(-0.82b*cosy-0.9b*siny)/1.36

solve this differential equation: y''-a(y'^2)-b(siny-a*cosy)=0 (a&b are cte.)