Recent content by mtbhrd
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Capacitor Circuit (Capacitor as source)
Right, thanks. So, with that voltage, charge on each cap (Q=VC) is 3.35v * C1 and then 3.35v * C2 I get Q1f=1.55x10^-5 C and Q2f=7.6x10^-6 C However, when I run conservation of energy, U=.5QV (Ui = U1f + U2f) it doesn't work... EDIT: Well, more simply put: Is it voltage or charge that is...- mtbhrd
- Post #5
- Forum: Introductory Physics Homework Help
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Capacitor Circuit (Capacitor as source)
You mention a large effective capacitance..As in combining the two as one effective capacitor in parallel (C1 + C2)? Using Q = VC , taking the original Q1i and using (C1 + C2) I get the same 3.35v as I got before.- mtbhrd
- Post #3
- Forum: Introductory Physics Homework Help
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Capacitor Circuit (Capacitor as source)
Homework Statement http://img141.imageshack.us/img141/6173/capcircuitji2.jpg Basically, I have to get charges and voltages as these switches are opened and closed on this capacitor circuit. First, Switch A closed, B open. (C1 is charged.) Then, switch A opens, and B closes. Vi=5v...- mtbhrd
- Thread
- Capacitor Circuit Source
- Replies: 4
- Forum: Introductory Physics Homework Help
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Capacitor Lab (Capacitor as source)
Maybe this should be moved to the Introductory Physics help forum?- mtbhrd
- Post #2
- Forum: Advanced Physics Homework Help
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Capacitor Lab (Capacitor as source)
Homework Statement http://img141.imageshack.us/img141/6173/capcircuitji2.jpg basically, I have to get charges and voltages as these switches are opened and closed on this capacitor circuit. First, Switch A closed, B open. (C1 is charged.) Then, switch A opens, and B closes. Vi=5v...- mtbhrd
- Thread
- Capacitor Lab Source
- Replies: 1
- Forum: Advanced Physics Homework Help