Capacitor Lab (Capacitor as source)

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SUMMARY

The discussion focuses on analyzing a capacitor circuit involving two capacitors, C1 and C2, with capacitances of 4.6x10^-6F and 2.3x10^-6F respectively. The initial voltage (Vi) is 5V, and the charge on the first capacitor (Q1i) is calculated as 2.3x10^-5 C using the formula Q = VC. The user explores charge conservation during the switching of capacitors and proposes that the final voltages (V1f and V2f) are equal, estimating Vf to be 3.35V. The approach to solving the problem is deemed correct, and the user contemplates whether to move the discussion to a more appropriate forum.

PREREQUISITES
  • Understanding of capacitor circuits and charge conservation principles
  • Familiarity with the formula Q = VC for calculating charge
  • Basic knowledge of voltage and capacitance relationships
  • Experience with circuit analysis techniques
NEXT STEPS
  • Study the principles of charge conservation in capacitor circuits
  • Learn about the effects of switching in capacitor networks
  • Explore advanced capacitor circuit analysis techniques
  • Investigate the role of voltage division in series capacitor circuits
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Students studying introductory physics, electrical engineering students, and anyone interested in understanding capacitor behavior in circuits.

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Homework Statement



http://img141.imageshack.us/img141/6173/capcircuitji2.jpg

basically, I have to get charges and voltages as these switches are opened and closed on this capacitor circuit.

First, Switch A closed, B open. (C1 is charged.)

Then, switch A opens, and B closes.

Vi=5v
C1=4.6x10^-6F
C2=2.3x10^-6F

Homework Equations



Q = VC

The Attempt at a Solution



Okay, so the first part is easy. Charge on the the first capacitor Q = VC, V=5v, Q1i= 2.3X10^-5 C

Now, the second part. Is charge conserved? So that
Q1i=Q1f+Q2f

Expanding that with Q=VC,
C1V1i = C1V1f + C2V2f

Can we say that V1f = V2f? So Vf would be 3.35v? Then charges could be found on each capacitor... Is this the correct way to go about this?
 
Last edited by a moderator:
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Maybe this should be moved to the Introductory Physics help forum?
 

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