Recent content by musicmaniac

  1. M

    What Is the Relative Speed of Two Parts of a Spacecraft After Detonation?

    is there anyone who knows if my relative speed between the two parts is correct?
  2. M

    What Is the Relative Speed of Two Parts of a Spacecraft After Detonation?

    yea you are right, they are moving directly away from each other, so I should add the two speeds together so .33333 m/s + .210526 m/s = .543859 m/s I hope I finally finished this problem, lol.
  3. M

    What Is the Relative Speed of Two Parts of a Spacecraft After Detonation?

    ok so right now here is my thought process: impulse is 400N*s so p final - p initial = 400 p final = 400 = 1200kg(v) 400/1200kg = .3333 m/s then, 400 = 1900kg(v) 400/-1900kg = -.210526 m/s so the two velocities are -.3333 m/s and .210526 m/s do these...
  4. M

    What Is the Relative Speed of Two Parts of a Spacecraft After Detonation?

    the parts should have impulses of opposite directions. One part will increase in momentum and the other will lose momentum, right?
  5. M

    What Is the Relative Speed of Two Parts of a Spacecraft After Detonation?

    does anyone have any ideas of where to go next? I am completely stuck.
  6. M

    What Is the Relative Speed of Two Parts of a Spacecraft After Detonation?

    so does that mean I should do 2(400)N/s= 1200kg+1900kg(v) so 800N/s= 3100kg(v) v= .258065m/s? I am really confused with understanding the way the information is being given to me in this problem. I feel the way I am interpreting the information is where I am getting stuck.
  7. M

    What Is the Relative Speed of Two Parts of a Spacecraft After Detonation?

    Hey everyone, Homework Statement A spacecraft is separated into two parts by detonating the explosive bolts that hold them together. The masses of the parts are 1200 kg and 1900 kg. The magnitude of the impulse on each part from the bolts is 400 N·s. With what relative speed do the two...
Back
Top