So obvious. I was looking for something really complicated.
Let u = (x/a)1/2
So x=au2, dx/du=2au
First simplify:
∫(x/a)1/2(x/(x-a)) dx
∫(x/a)1/2( 1 + a/(x-a) ) dx
Substitute by u:
∫u( 1 + a/(au2-a) ) 2au du
2a∫u2( 1 + 1/(u2-1) ) du
2/3au3 + 2a∫u2/(u2-1) du
2/3au3 + 2a∫(1 +...
Homework Statement
Hi. My first post!
I'm trying to solve for where a is a constant:
∫ (x/a)1/2*(x/(x-a)) dx
Homework Equations
See above
The Attempt at a Solution
I've tried integration by parts by setting u=(x/a)1/2 but I end up having to solve ∫ (x/a)1/2ln(x-a) - which I...