Recent content by mvr01

Can somebody please explain how to read a binary phase diagram.

Yes you're right,,, The question is the atomic density of 6.04 X 10^22 atoms per cm^3. I missed out the units. so would this mean, (6.04 X 10^22 cm^3 / 1.023 X 10^23) x 26.98 amu = 2.7 g/cm^3

Sorry,, I hope I am not annoying you. I am getting mixed answers. Can you please work it out for me... Im gettng volume of 6.04 X 10^22 = 4.470 X10^-23, therefore the mass density equaling 3.645 X 10^46.. or (6.04 X 10^22 / 9.98 ) X 26.98 = 1.6g/cm^3 Im lost

Thanks dickfore... so is this right? p = (6.04 X 10^22 / 6.023 X 10 ^23) x 26.98 = 2.7g

Can anyone help. How do I calculate mass density of aluminium, given the atomic density of 6.04 X 10^22. I understand that Density = Mass/Volume. but the question confuses me. Thanks