Recent content by mykoolspam

Ah crap. i think i might have posted the question above the question i actually needed. But k nvm i figured out the answer :) Thanks anyways guys

..yeahhhh...okkay? Im trying to figure it out without that formula..

Homework Statement A 275 N box is sliding down a frictionless inclined plane. If the incline makes an angle of 30.0 degrees with the horizontal, what is the acceleration along the incline? I don't need to know how to figure out the solution to this problem - yet, atleast. Im trying to...

Ohh haha nevermind i got it! Thanks ALLOTT for your help!

hm. ok so... -14.715 = 1.5a -29.43 = 3.0 * -a i get -9.81 and 9.81 = a What ami missing this time? x.x

m2 = T-29.43=3.0a so.. T1 = 1.5a + 14.715 T2 = 3.0a + 29.43 so..i made T1=T2, but it doesn't work out. I thought about it and i figured T1 can't equal T2 anyways. ha. Do i multiply the two equations or..?

hmm. [Sum of forces] = T - Fg = T - (mg) = T - 14.715 therefore.. T - 14.715 = 1.5 * a hhmmm..what Am I Missing?

Oops. Yeah i often use Fn and T interchangeably. Are they the same equations? Well, mass one is accelerating upwards while mass two is being pulled down by gravity. So: Fg = 3.0kg * 9.81 = 29.43 N [MASS 2] And since mass one is being pulled up: T = ma? T = 1.5 kg * a So.. [Sum of Forces] =...

The two forces are Fg and Fn, right? So..two equations? mass 1 = 1.5 kg - Fg = mg = 1.5kg x 9.81 mass 2 - 3.0 kg - Fg = 3.0 x 9.81 hmm I am so lost.

Homework Statement Two masses, 1.5 KG and 3.0 KG, are tied together by a light string and looped over a frictionless pully. They are allowed to hang freely. Determine the magnitude of the acceleration for each mass. [Answer: 3.3 m/s2) Homework Equations Fnet = ma Fg = mg The...