Recent content by myvow

I know what you mean sir if I use (x/100)^2, .x will be the mole of HI right? But in the numerator,did you see((0.5/2/100)-0.5x) if x =mole, minus 0.5x this is the mole instead of concentration

Does numerator will not be wrong?

For example 14 is the mole of h2,so 14/5=2.8 which is concentration of h2, right? OK then there is 0.5g of h2, 0.5/2=0.25mol 0.25/100=1.25*10^-3M What wrong with me?

You're using it in the denominator for hydrogen and iodine concentrations What it mean...

((45/253.8)/100) ？？this way？？

Yes, but molarity = mole/volume Does not volume is necessary?

100L The volume

6.865 = x^2 / ((45/253.8/100)-0.5x)((0.5/2/100)-0.5x) This equation is OK?because the mole ratio of H2 to Hi is 1:2 So [HI]=x=5.33*10-4M HI =6.813g?

Kc1 = (5.8*2/5)^2 / (14/5)(1.4/5) = 6.865 6.865 = [HI]^2 / (45/253.8/100)(0.5/2/100) [HI] = 5.52x10^-3 M mass no of HI = [HI] x (126.9+1) x 100 = 70.6g is it correct? And how to do 3bii I GOT 3bi Kc2 = [HCl(g)]^2/ / Kc(1) [H2(g)] [Cl2(g)]

For this question,why Ka =(ch3coo-)(h+)/(ch3cooh) instead of Ka =(ch3coo +x)(x)/(ch3cooh-x) ?