Recent content by n00by

Does anyone know how to do this proof?

Homework Statement Use the equivalence p\rightarrow(r \rightarrow s) \equiv p\wedge r\rightarrow s to rewrite the following problem before the proof. Homework Equations [p\rightarrow (q\rightarrow r)]\wedge (p\rightarrow q) \tautologicallyimplies (p\rightarrow r) The Attempt at a...

I'm supposed to "solve" the differential equation. Does that not require solving for y?

Thanks for your help, I really appreciate it. Here's what I tried: \frac{1}{y^2-1} = \frac{1}{(y+1)(y-1)} = \frac {A}{(y+1)} + \frac{B}{(y-1)} 1 = A(y-1) + B(y+1) y = 1: 1 = 0 + B(2) \iff B = \frac{1}{2} y = -1: 1 = A(-2) + 0 \iff A = -\frac{1}{2} \therefore \frac{1}{y^2-1} =...

Hi, I don't see how I can apply partial fractions to \frac {dy}{y^2-1} ?

The equation I'm trying to solve is \frac{dy}{dx} = \frac{y^2 - 1}{x^2-1}, given y(2) = 2 The methods I'm somewhat familiar with are separation of variables, integrating factor, and exact. I tried this: \frac{dy}{dx} = \frac{y^2 - 1}{x^2-1} (x^2 - 1)dy = (y^2-1)dx (x^2 - 1)dy -...