Recent content by n_nason

Oh, right that makes sense. Still not getting the correct answer, 1t+4.9t^2+27=-24.8t+9.92+4.9t^2-3.92t+.784+.8 is my simplified answer canceling acceleration and solving for t I get, 29.72t=-15.496 t=-1.92

So say I make the second half of my equation... -24.8(t-.4)-4.9(t-.4)^2 Then my equation would be... 1t+4.9t^2+27=-24.8(t-.4)-4.9(t-.4)^2 My acceleration would not cancel, is that the right track?

Homework Statement A red ball is thrown down with an initial speed of 1.0 m/s from a height of 27.0 meters above the ground. Then, 0.4 seconds after the red ball is thrown, a blue ball is thrown upward with an initial speed of 24.8 m/s, from a height of 0.8 meters above the ground. The force...