The Fg on Mass B is mBg, while Fg on the box cancels out with the normal force on the box, so the only Fg involved is FgB. Ignoring that, is this equation correct?
m2 = (m1a + Ff) / (g - a) with friction being the force that the Newton Spring Scale showed when pulling at a constant speed?
My first little paragraph was based off of FBDs I drew. But, here they are in internet-form.
FBDs
Edit: Wait... if it took 5N to move the box at constant speed, the friction was 5N. That gives me a mass of 1.436kg instead.
Okay. So for the box, the force responsible for its acceleration is the tension, and it is reduced by friction for the net force in x. For the mass, it accelerates due to gravity, so mg, and the net force is mg less the tension force.
The equation for the tension force is:
Ft = m2(g-a)
Mass 2...
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