ok I used the ln property and here is what I got.
ln(7x+1)^1/2+ln(3x^2+x)^5-ln(x^2-3)^3+lne^2x
1/2ln(7x+1) +5ln(3x^2+x)-3ln(x^2-3)+2x
and finally 1/2*7/7x+1+5*6x/3x^2+x -3*2x/x^2-3 + 2
am I right?
The question is to compute the derivative of
ln (7x+1)^1/2 (3X^2+x)^5
(x^2-3)^3 e^2x
the ln is for both the numerator and denominator
I tried the chain rule and came up with this
1
(7x+1)^1/2 (3x^2+x)^5
(x^2-3)^3 e^2x...