Recent content by natalie.*

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    What Are the Quantum Limits of Cooling Sodium Atoms in an Atom Trap?

    For anyone else googling this problem or anything: I ended up figuring it out. The delta v you can find with the Heisenberg uncertainty principle is around 0 m/s, so: -0.5*(delta v) <= v <= 0.5*(delta v) Then your v_rms=0.25*(delta v) and you sub that into the equation given to find T (in...
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    What Are the Quantum Limits of Cooling Sodium Atoms in an Atom Trap?

    Homework Statement Physicists use laser beams to create an "atom trap" in which atoms are confined within a spherical region of space with a diameter of about 1 mm. The scientists have been able to cool the atoms in an atom trap to a temperature of approximately 1 nK, which is extremely close...
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    Finding points where electric potential is 0

    The directions ended up throwing me off a little, but I finally got it with someone else's help. Thank you! For anyone else: Answer 1: E_{1}=\frac{K|q_{1}|}{r_{1}^{2}}+\frac{K|q_{2}|}{(d-r_{1})^{2}} Answer 2: E_{2}=\frac{K|q_{1}|}{r_{2}^{2}}-\frac{K|q_{2}|}{(d+r_{2})^{2}} Note that...
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    Finding points where electric potential is 0

    Awesome, so I know what the two points are now, and I've double checked that the electric potential at both of those points is 0. I'm still getting the wrong answer though, but I have a few more tries. Since it asks for the magnitude of the electric field, I'm using...
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    Finding points where electric potential is 0

    Yeah, that makes sense to me, because that's how I worked out Part A, but I got the wrong answer for this. If I work it out so that r_{1} is to the left of q_{1}, then r_{2}=d+r_{1}. If I simplify my formula out again, I just get the negative of my first answer, which to me just means my math...
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    Finding points where electric potential is 0

    Hi, this is my first time posting on the forums, so if I make any mistakes, I'm sorry. Homework Statement This question has already been started here: https://www.physicsforums.com/showthread.php?t=449070 but they never got to part (b). PART A A -10.1 nC point charge and a +18.9 nC...
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