Firstly, thank you for the responses.
I agree I wasn't clear enough in my initial post. I'll try to correct that now.
Since
z = x + iy
We can rearrange to get
x = z -iy
therefore
\frac{∂x}{∂z} = \frac{∂z}{∂z} = 1
Similarly for y we get
\frac{∂y}{∂z} = -i
Then using the...
Hello,
I'm sorry if I'm not posting this to the correct place - this is my first post on PhysicsForums.com
My question regards derivatives of analytic functions. Here it goes:
Let
w(z) = u(x,y) +iv(x,y)
be an analytic function,
where
z = x + iy,
for some x,y that are real...