Recent content by navaq

Yes, it really is. Ka (nitrous acid) = 5,1 x 10^(-4)

Titrant [HNO2]= 0.10 mol/dm3 v= 25ml = 0.025 dm3 + Analyte [NaOH]= 0.125 mol/dm3 v= 20ml = 0.02 dm3 Question is: What is the ph after adding a volume 10ml of titrant? I know the answer is ph= 4,3 I'm not allowed to use Henderson Hasselbach equation. This is the...