Recent content by nayfie

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    Closed Line Integral Homework - Computing a Hypotenuse

    Thank you both for the replies, very helpful!
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    Closed Line Integral Homework - Computing a Hypotenuse

    Homework Statement -- Homework Equations -- The Attempt at a Solution This isn't really a proper homework question so I'll just write my problem here: I'm trying to compute a closed line integral over a triangular region. I have calculated two of the sides, but am now left...
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    What do the symbols in the line integral equation mean?

    Firstly, thanks for the reply. Can you describe what you mean by a parametrization? In your example you've used a range, but in an example we did in class the lecturer used the function of the curve. I'm confused :(
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    What do the symbols in the line integral equation mean?

    Hey guys. I've just had a few lectures on line integrals. My lecturer has told me the following: \int_{C}^{} f(s) \text{d}s = \int_{a}^{b} f(\gamma(t))\|\gamma'(t)\| \text{d}t Unfortunately he hasn't explained this topic very well. I understand what's going on with a line integral but have...
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    Gaussian Integral: How to Solve for x^4 Term?

    Took your advice and the answer popped out straight away. How did I not think of this? Thanks mate :)
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    Gaussian Integral: How to Solve for x^4 Term?

    I haven't been taught that yet. Is that the only way to solve this integral? I've been reading the related articles but can't work out how to apply it to this question. Unfortunately it seems my physics course is ahead of my maths course.
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    Gaussian Integral: How to Solve for x^4 Term?

    Homework Statement I'm having difficulty solving the following integral. \int_{-\infty}^{\infty} x^{4}e^{-2\alpha x^{2}} \text{d}x Homework Equations \int_{-\infty}^{\infty} e^{-\alpha x^{2}} \text{d}x = \sqrt{\frac{\pi}{\alpha}} \int_{-\infty}^{\infty} x^{2}e^{-\alpha x^{2}}...
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    Vector Subspaces: Understanding Closure Properties

    Just took another look at this question and might have solved it. u = (a, b), v = (c, d), u + v = (a + c, b + d) (a + c)^{2} + (b + d)^{2} = 0 a^{2} + 2ac + c^{2} + b^{2} + 2bd + d^{2} = 0 But, we know from the constraints of the subspace that; a^{2} + b^{2} = 0; c^{2} + b^{2} = 0...
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    Vector Subspaces: Understanding Closure Properties

    Hello :) I've been doing a lot of work on subspaces but have come across this question and need a bit of help! Homework Statement W = {(x, y) \in R^{2} | x^{2} + y^{2} = 0} Homework Equations 1. 0 ∈ W 2. ∀ u,v ∈ W; u+v ∈ W 3. ∀ c ∈ R and u ∈ W; cu ∈ W The Attempt at a...
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    Efficient Differentiation of Hyperbolic Integrals

    :) Thank you all very much for the help!
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    Efficient Differentiation of Hyperbolic Integrals

    Actually now that I look at it again I think the chain rule needs to be applied twice? f(x) = G(cosh(x^{2})) f'(x) = G'(cosh(x^{2})) = g(cosh(x^{2})).sinh(x^2).2x f'(x) = tanh(cosh^{2}(x^{2})).sinh(x^{2}).2x It's been a long day :(
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    Efficient Differentiation of Hyperbolic Integrals

    First of all, thank you all for the contributions :) I think I have arrived at an answer! Let me know if I've made a mistake. ----------------------------------------------------------------- f(x) = \int^{cosh(x^{2})}_{0} tanh(t^{2})dt, let tanh(t^2) = g(t) f(x) = G(cosh(x^{2})) -...
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    Efficient Differentiation of Hyperbolic Integrals

    You mean that \frac{d}{dx} \int^{x}_{a} f(t)dt = f(x)? Does this imply that \frac{d}{dx} \int^{cosh(x^{2})}_{0} tanh(t^2)dt = tanh(cosh^2(x^2))?
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    Efficient Differentiation of Hyperbolic Integrals

    Hello again :) I get the feeling I'm missing some kind of 'trick', as this is proving a very difficult question :( I'll write out my frustration below; Homework Statement Find f'(x) if f(x) = \int^{cosh(x^{2})}_{0} tanh(t^2)dt Homework Equations --- The Attempt at a Solution My idea was...
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    Proving if a subset is a subspace

    I have followed both of your replies and have proven that W is indeed a subspace (as it satisfies the conditions). I find it easier to understand what's going on if I have a geometric interpretation. Thank you both very much for the replies, you've ended a lot of frustration :)
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