the equation I am given doesn't have an x variable so am I to assume k= 1.1? or w=-3.3? And if w=-3.3 then the frequency would be a negative number? is that possible?
A string has a linear mass density of 3.4 g/m. When a sinusoidal wave is created on the string with a speed of 32.8 cm/s the displacement of the particles on the string at x=13.3 cm varies with time according to the following equation: y=4.4sin[1.1-3.3 t] cm. Find the frequency.
Well, I am...
ok here is what I did:
v=-wAsin(wt+phi)
a=dv/dt=-Aw^2cos(wt+phi)
I set phi=0 (maybe went wrong here?) and...wait a second, hmm. Ok, I had to set t=0 also, then I just solve for A. Nothing like solving a problem at 2:02 am. Thanks for the patience Tide.
So if the acceleration in the direction of the orcillation exceeds g the brick will fly off...? I tried taking the derivative of the velocity equation -wAsin(wt+phi) but I got a wrong answer. This question is driving me nuts...
A brick is resting atop a piston that is moving vertically with simple harmonic motion of period 1.08 s. At what amplitude will the brick separate from the piston?
I came across this question reviewing for my test next Thursday. Anyway, I can calculate the angular frequency using the...
While running, a person dissipates about 0.554 J of mechanical energy per step per kilogram of body mass. If a 62.5 kg runner dissipates a power of 65.4 W during a race, how fast is the person running? Assume a running step is 1.50 m in length.
Well I know that the person loses 34.6 J of...
I did assume that when the angle is zero E=0 and when the angle is 90 E=mgh=64.8, so I thought the answer would be (sin30.9)(mgh), but that answer was incorrect. I also tried (sin59.1)(mgh) which was also incorrect, I am not sure where to go from here.
A 30.3 N child is in a swing that is attached to ropes 2.14 m long. What is the gravitational potential energy when the ropes make a 30.9° angle with the vertical?
So far I've tried 6 different answers ranging between 0-64.8 J and no luck. Need a clue to get me on the right track. Thanks...
Well, there is the force of gravity and the normal force but they are in the vertical direction...all that tells me is that the normal force equals the weight and i can get the frictional force with that piece of info...i don't believe there are any other forces acting on the wood block, 2 in...
I did try using Newtons second law to determine the net force on the wood block. In this case I would have to factor in the frictional force...ie.
F(bullet)-F(friction)=m(bullet+block)a, but i ran into a wall because i don't have the acceleration or F(bullet).