Recent content by NCampbell

I am not sure? I don't see the connection between r^2 and how to find theta that way, are you also in this class?

To convert to polar form we use r=sqrt(x^2+y^2) and theta= arctan(y/x) where x and y are your x and y components

If we know r (and using polar coordinates) that x=rcos\theta and y=rsin\theta then isn't \theta=arctan(y/x)? I am having a difficult time with this question so I am not entirely sure on what to do either.

Thank You Cepheid! that cleared things up for me I was lost after my lecture on vector calculus today amongst the different notations and how each of the components are affected differently, and no I wasn't given F(t) just that a rock was through off a cliff at angle (theta) from the horizontal

I am sorry I am not grasping the concept of integrating vectors could you provide some direction?

Homework Statement a) Starting From Newtons second law, find the location of the rock as a function of time in horizontal and vertical Cartesian coordinates b) If r(t) is the distance the rock is from its starting point, what is the maximum value of θ for which r will continually increase as...