Recent content by NCBryan

Thank you for your input. It could very well be 1 and 2. I have been doing a lot of experiments since Borek turned me on to the partition coefficient thingy. Thank you again Borek. I have determined/observed: 1. The amount of water is only .5+- gallons 2. Additionally there is 1.5+- gallons...

OK, I found this so I get it now. Thanks for guiding me to this. I am still open to any other suggestions. Thanks

Let me say one thing, I am dyslexic so it is difficult for me to perceive certain things. I am good with math (not so much with word problems) but sometimes I can't tell the chicken from the egg. I appreciate you sharing this with me, I love learning, but I am one of god's curl jokes, a...

Yes, E10 is derived by weight. Ok i think we are on the right track, more in layman's terms and should suffice. So basically the gas had .5 gallons of water in it and the ethanol being designed to dry the gas was attracted to the water and thus their should be no ethanol left in the gas? (+-)...

I understand that. I have gas with 10% ethanol, water is added to the gas, water then (In some way??) contains 73% ethanol, how do I explain how the gas that only has 10% ethanol can cause the water to contain 7 times more ethanol. Saying ethanol dissolves in both gas and water in no way...

That seems to be very close but not exactly what I am looking for because ethanol and gas can mix together.

I have to sue the pump owner. He says it is impossible for water to come out of the pump, then he says other cars never made it out of the parking lot when it happen to other customers. Because it is unlikely that the judge is going to be a mechanic or a chemist, I will need to explain it to him...

I purchased 22.752 gallons of gasoline containing +- 10% ethanol dispensing it into a 23 gallon gas tank. Then I drove 23 miles (mostly up hill) to a job site. At lunch time I was not able to crank the engine. The symptoms were clear, it was water in the gas. I have a video if you want to see...