- #1
NCBryan
- 8
- 0
I purchased 22.752 gallons of gasoline containing +- 10% ethanol dispensing it into a 23 gallon gas tank. Then I drove 23 miles (mostly up hill) to a job site. At lunch time I was not able to crank the engine. The symptoms were clear, it was water in the gas. I have a video if you want to see how I did it but long story short I got 2+ gallons of water out of the tank. Well the only place that water could have come from is the gas pump. This had me completely dumbfounded as I know you cannot burn water. Non the less I complained to the pump owner and he said I could not have made it out of the parking lot with that much water in my tank, normally I would agree with that statement but the facts suggest otherwise. After racking my brain for a minute it occurred to me that the gas contained alcohol (ethanol). I know from my Bunsen burner what that means. Fortunately I had the foresight to save the water. I happen to have a separatory funnel a beaker and a hydrometer. So I wanted to see how much alcohol was in the water and was it possible it would partially burn. There is only 10% in the gas so I was thinking it might be as high as 8%. LOL (I did it for you). Then maybe this 8% alcohol and the 50% gas I was getting from the fuel pump would be enough to burn. After checking the alcohol content of the water it came out to 73% (which will burn in my Bunsen burner). Well that blew my mind. Now my problem is going to be, how do I explain to a judge that it is possible for gas containing 10% alcohol to produce water containing 73% alcohol?
It would be so helpful if you can explain it to me.
Thank you.
It would be so helpful if you can explain it to me.
Thank you.