Recent content by ndogg

Thanks again, Ja4Coltrane!

Sorry, I don't think I was clear on what the problem is. Here it is: There are two people connected to a pully. One is holding the rope and touching the ground, the other is suspended in the air and hanging on to the pully. Both are perfectly still -- there is zero velocity. Now, what I need to...

Thanks! Problem solved.

Oh yes, both persons are still. But if one person is pulling with a force of 700 N, shouldn't that accelerate the person on the other side of the pully of mass 60 kg?

So, in this case, friction = centripetal force?

Yes, thank you for simplifying things. The only thing I don't understand is, if person one (mass 70 kg) is pulling down on the rope with 700 N, shouldn't person two (mass 60 kg) be accelerated upward because of the net force of 100 N?

So the direction of friction is in the same direction as the centripetal force (which is the center of the record)? Shouldn't it be in the opposite direction because there has to be an equal and opposite reaction?

So then the forces for person one are 700 N upward and 700 N downward; and for person two 600 N upward and 600 N downward. I don't understand why they don't affect each other since they are both pulling down on the rope.

The object itself is not accelerating because it remains still on the record. So is there 0 friction?

Thanks for posting. So the forces that act on person one are 600 N upward and 700 N downard; and for person two the forces are 700 N upward and 600 N downward. Does that sound right?

If a rope of mass 10 kg is connected to a hook on the top and is supporting a mass of 15 kg at the bottom, what is the rope's tension?

If a person of mass 70 kg is holding onto a rope that is connected to a pully and is suspending a person of mass 60 kg on the other side, what are the forces acting on each person. Oh, and both persons are still (0 velocity).

If an object is placed on a record that is spinning, what is the direction of the force of friction?

Oh yeah, I don't know what I was thinking. There is still weight, so the force pushing down is 60 N. I still would like to have someone clarify #3.

1) The hook exerts a force of 150 N on the rope. So would the tension in the rope just be 150 N? Or do you have to take into account the mass of the 10 kg rope, in which case the tension would be 250 N or 200 N? 2) The 6 kg mass does not have weight because it is suspended in the air, right?