- #1
ndogg
- 24
- 0
If a person of mass 70 kg is holding onto a rope that is connected to a pully and is suspending a person of mass 60 kg on the other side, what are the forces acting on each person. Oh, and both persons are still (0 velocity).
Thanks for posting. So the forces that act on person one are 600 N upward and 700 N downard; and for person two the forces are 700 N upward and 600 N downward. Does that sound right?Ja4Coltrane said:Assuming that the system is not accelerating, just draw some free body diagrams and use Newton's third law for tension.
Ja4Coltrane said:NO IM SORRY!
Not T-700
700-T
the person is falling! I'm so sorry for that confusion!
The formula for calculating the force on a 70kg person holding a rope onto a pulley is F = m*g, where F is the force, m is the mass (70kg), and g is the acceleration due to gravity (9.8m/s^2).
The angle of the rope does not affect the force on the person. The force is solely determined by the person's weight (70kg) and the acceleration due to gravity (9.8m/s^2).
No, the force on the person is not constant while holding the rope onto a pulley. As the person pulls down on the rope, the force increases due to the tension in the rope. Once the person stops pulling, the force decreases back to their weight (70kg).
The radius of the pulley does not directly affect the force on the person. However, a smaller pulley may require the person to pull with more force to lift the same weight, while a larger pulley may require less force. This is due to the difference in the amount of rope being pulled and the distribution of weight on the pulley.
Other factors that can affect the force on a 70kg person holding a rope onto a pulley include the mass of the object being lifted, the friction between the pulley and the rope, and the angle of the rope relative to the ground. Additionally, if the person is also moving horizontally while holding the rope, the force will also be affected by their acceleration and the friction between their feet and the ground.