Recent content by nedf

Thanks. At the end of the page on https://www.mathworks.com/help/matlab/ref/dot.html Why is the dot product defined this way instead? Wouldnt the answer be different? $\mathbf a \cdot \mathbf b = \sum\overline a_i{b_i}$ Also, i computed the orth on matlab: Why is it different from...

Wolframalpha provides this solution: Wolfram|Alpha: Computational Knowledge EngineHowever when i compute the second term v2 = x2 - (x2.v1)/(v1.v1) * v1 The result is different from that of above. What's wrong? Wolfram|Alpha: Computational Knowledge Engine)

I will get this? [1 1 1 1] [0 1 1 1] [0 0 1 1] [0 0 0 1] How do I prove that this matrix has same determinant as the original one?

Given a n x n matrix whose (i,j)-th entry is i or j, whichever smaller, eg. [1, 1, 1, 1] [1, 2, 2, 2] [1, 2, 3, 3] [1, 2, 3, 4] The determinant of any such matrix is 1. How do I prove this? Tried induction but the assumption would only help me to compute the term for Ann mirror.