Recent content by needhlp

What I meant was in a series, the Q's in Q=CV are the same for each capacitor in that series and in a parallel series the V's in Q=CV are the same. Thanks for explaining the differences, why the book couldn't make it that easy I'll never understand

I was distinguishing between capacitor C2 and C, but since they are equal it would just be C&C. Does that clear it up? If not I did this C*C/C+C=C/2 current, charge, voltage...I still can't get the differenct between them and it's really hard becuase I can't picture the difference in my head...

I'm sorry, I made a huge mathematical mistake from the beginning, I edited it so it should make better sense now. when I say the capacitors in the series, I'm talking about the one labled C2 in my picture and the one right below it. Then the one that is parallel to those 2 would be the...

Capacitance across the series is C2*C/C+C or C2*C/2 which I assume I can make into just C^2/2Csince all the C's are equal Capacitance across all three would be 3C/2 Then if I make it all into just 1 capactior it would be 3C/5 The current across it would be q=CV so q=10(3*10)/(5) since...

Parallel capacitors is q/V so C1+C2+C3... Series capacitors are 1/(1/C1+1/c2+1/C3) Yes all the Cs are equal. I think I had my series equation wrong but I just don't understand it. I know I have to use the voltage across the capactiors but I'm also not sure how to find that.

Ok, the capacitance across the 3 would be C+ 1/C+C then q= VC+ V/C+C or am I completely wrong?

Capacitance -- How handle multiple caps in series and parallel? I can't draw the circut for the cuestion so I attached it. I am having trouble finding the charge across capacitor 2. I don't understand what to do with the 3 capactiors right in that group and how to figure the change in voltage

ah, too many q's running around. Thank you

I am having trouble with this derivation: f(q)=q(Q-q). We want to find the values that maximize the vaule of q so the book sets the derivative equal to 0 and gets Q-2q=0 When I try to do the derivative of f(q)=q(Q-q), I used the product rule 1(Q-q) + q(Q-1)=0 Q-q+Qq-q=0 Q+Qq-2q=0 I...