Maximizing q in f(q)=q(Q-q) Derivation | Simplified Steps

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I am having trouble with this derivation: f(q)=q(Q-q). We want to find the values that maximize the vaule of q so the book sets the derivative equal to 0 and gets Q-2q=0

When I try to do the derivative of f(q)=q(Q-q), I used the product rule

1(Q-q) + q(Q-1)=0
Q-q+Qq-q=0
Q+Qq-2q=0

I have an extra (Qq) I don't know how to get rid of.
 
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needhlp said:
I am having trouble with this derivation: f(q)=q(Q-q). We want to find the values that maximize the vaule of q so the book sets the derivative equal to 0 and gets Q-2q=0

When I try to do the derivative of f(q)=q(Q-q), I used the product rule

1(Q-q) + q(Q-1)=0
There's a mistake above. d/dq(Q - q) = -1, not Q - 1. Q is a constant in this function.
needhlp said:
Q-q+Qq-q=0
Q+Qq-2q=0

I have an extra (Qq) I don't know how to get rid of.
 
ah, too many q's running around. Thank you
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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