Recent content by needlottahelp

ok so I tried fitting the x and y components into various kinematics equations but I can't seem to isolate any variables to find the angle I get things like 19.6h = Vy^2 or 3h = Vx t any hints?

Homework Statement A projectile is fired in such a way that its horizontal range is equal to three times its maximum height. What is the angle of projection? Homework Equations Kinematics Equations The Attempt at a Solution I'm not even sure where to start. Can someone point me in...

1 meter = 10^9 nanometers I believe

I'm not exactly sure but could the fact that the Electric field is going in the y direction while the electron is moving in the x direction?

yes I believe so

Its negative because of the frame of reference. remember displacement is a vector? its only negative because its downward. the opposite would be true the distance is just 3.40 x 10^-8

well vy0 is the initial velocity in the y-direction. In other words the vertical direction. The ink was ejected horizontally 12 m/s so that's why the vy0 = 0 m/s

I see no problem with the time. The equation you used was correct too but the problem is that vyo = 0 m/s and not twelve because the angle of elevation from the horizontal is 0 therefore vyo = sin (0 degrees) (12 m/s) = 0 m/s

the normal force should be equal to the weight of Block B

oh hahah ok well Given: vi= 45 m/s and t = 4 so vyi = sin (40) vi and vxi = cos (40) vi and to find the speed in four seconds you use the kinematics equation vyf = vyi + (ay) (t) and velocity in the horizontal remains constant since ax = 0 find those to values and vf = sqrt ( vyf^2 + vxf...

i think basically its just asking for the height the ink dropped from the pen onto the paper

You want to find the mass of block C so that it moves block A but not too large that it overcomes the static friction between block A and block B I believe. So find the static friction and divide it by g to find the mass of Block C static friction = (coefficient of static friction)...

find the vy and the vx after 4 seconds and find the resultant vector.

umm...i think you use x = (v0) (t) and solve for time then use the time for one of the kinematics equation as if it were free fall? does that make sense to you?

yeah. i think sometimes g is rounded to 10 or 9.81. i think so unless the problem states otherwise. So use that to find the time. If you want the max height, you should probably use this kinematic equation: vyf^2 = vyi^2 + 2at Note: a = -g in this case For the range, you use d = (vx) (t)...