Electron in a uniform field, acceleration

AI Thread Summary
An electron with an initial velocity of 2.5 × 10^6 m/s in the x direction enters a uniform electric field of 320 N/C in the y direction. The acceleration of the electron is calculated using the formula a = QE/m, resulting in an acceleration of approximately 5.62 × 10^13 m/s². There is a discussion about the direction of the acceleration, which is upward due to the electric field, while the electron's initial motion is horizontal. It's noted that the final answer should be rounded to three significant digits. Clarification on the direction of the acceleration in the answer entry is also suggested.
Specialmias
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Homework Statement



An electron has an initial velocity of 2.5 ×
106 m/s in the x direction. It enters a uniform
electric field ~E = (320 N/C) ˆj which is in the
y direction.
The charge and mass of an electron are
1.6×10−19 C and 9.11×10−31 kg, respectively.
Find the acceleration of the electron. An-
swer in units of m/s2.

Homework Equations



MA=QE
a=QE/m



The Attempt at a Solution



320*(1.6e-19)/(9.11e-31)= 5.62019759e13
Attempted to insert exactly as shown and was marked wrong. I can't seem to find a reason why the answer to this is wrong and I've hit a bit of roadblock so to speak

Any help is appreciated
 
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I'm not exactly sure but could the fact that the Electric field is going in the y direction while the electron is moving in the x direction?
 
Your answer looks good to me.
The acceleration will be upward - have you a way to indicate the direction in your entry?
Also, you have used 3-digit accuracy in e, m and E so your final answer should be rounded to 3 digits.
 
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