Recent content by Neelima

You treat 1.2m as displacement along vertical. 5.3 m as displacement along horizontal. And proceed. You will get

Method is correct. But you should not square the position. It is like U= ( K x q1 x q2) / r I think do

Considering the figure as it is , Force on X due to Y is towards left Force on X due to Z is towards right. As net force on X is towards left ( see the attachment ). F(y) > F (z). F (net) = F(y) - F( z) 50 x 10^(-5) = 25 x 10^ (-5) - (20xI /6) x 10^(-5) Solving we get negative value for I which...

My solution to problem. Attachment

Since resistance values are given we need think about type of wire. From situation they are in parallel connection. Please see the attachment