Recent content by neromax

It is a Bitzer semi-hermetic 18.4 kW, controlled by a frequency controller. I thought that one could vary the pressure on the condenser side, thus achieving a different temperature. By varying the speed of the compressor one would be able to decrease or increase the flow of the refrigerant. But...

Hi! The problem is in connection with variable speed heat pumps used for heating purposes, where the source/reservoir is ground/rock. The ground has temperatures around 5-7 celsius. Is it correct that these systems only can deliver one temperature at one load? E.g.: at 30 % of full power, it...

Solved it! I finally understood how it worked :wink: D\frac{\partial}{\partial x} C(x,t) = -BD \frac{\partial}{\partial x}\int_0^{\frac{x}{2\sqrt{Dt}}} e^{-y^2}dy = -BD e^{-\left(\frac{x}{2\sqrt{Dt}}\right)^2} \frac{\partial}{\partial x} \left(\frac{x}{2\sqrt{Dt}}\right) = -BD...

Is this the correct change of limits and function of the integral? \frac{\partial}{\partial x} C(x,t) = -B \frac{\partial}{\partial x}\int_0^{\frac{x}{2\sqrt{Dt}}} e^{-y^2}dy = -B \frac{\partial}{\partial x} \int_0^x e^{-y^2\left(4Dt \right)^{-1}}dy = -B e^{-x^2\left(4Dt \right)^{-1}}\\...

@HallsofIvy - Thanks for a reply. The problem bugging me though, is that i do not have x , but \frac{x}{2\sqrt{Dt}}, such that: \frac{2}{\sqrt{\pi}} \frac{\partial}{\partial x} \int_0^{\frac{x}{2\sqrt{Dt}}} e^{-y^2}dy

Homework Statement I am to prove that a solution to the differential equation Fick's second law is valid by substitution. Homework Equations Fick's second law: \frac{\partial C}{\partial t} = \frac{\partial}{\partial x} \left( D \frac{C}{\partial x} \right) Solution to Fick's second...