Recent content by Netsurfer733

Oh god...lol, I've been really stressed and all over the place lately, I feel dumb for missing that XD Thanks a lot rock, got it!

Yea I...really just can't see another way out besides dong the following: J = n_e * e * v_d 588235 = 6*10^28 * 1.6*10^-19 * v_d v_d = 6.13*10^-5 m/s = 6.13*10^-11 um/s Where is this wrong...? /o_o\ 1.6*10^-19 is the charge of an electron...6*10^28 1/m^3 is the electron density, and 588235...

Oh man lol, sorry about that! It's the electron density for aluminum: 6.0*10^28 1/m^3. But yea, like...I don't know. I've tried 6.13 * 10^-5, 6.13*10^-11, 6.13*10^-6, and 61.3*10^-6, with no luck. Should I try one of these again just in case, or what do you think it is?

No, that wasn't it... It's really quite frustrating. This looks to be essentially the only part on the assignment I won't understand/get. Does anyone know what's going on with it?

Hah, I should've known; thanks, I got the first part. The second part, however, I got wrong: I used J = n_e * e * v_d with the values: 588235 = 6*10^28 * 1.6*10^-19 * v_d and solved for v_d I got 6.13*10^-5 m/s and then converted to 6.13*10^-11 micrometers / second, and got it wrong...

Homework Statement "The current in a 1.70mm x 1.70mm square aluminum wire is 1.70 A. What are (a) the current density [in MA/m^2] and (b) the electron drift speed [in micrometers/second]?" Homework Equations J = I/A The Attempt at a Solution I plugged in the values for current...

I did - but I apparently suffered a flurry of math errors. I got it anyway :)

Homework Statement "Two 2.1cm x 2.1cm plates that form a parallel-plate capacitor are charged to +- 0.705 nC. What is the potential difference across the capacitor if the spacing between the plates is 1.20mm? " Homework Equations C = Q/V C = epsilon * A/d The Attempt at a Solution I...

Homework Statement What is the electric potential at the point indicated with the dot in the figure? http://img842.imageshack.us/i/29ex26.jpg/ Homework Equations E = V_c / d ? V = E*s? V = k * q / r ? The Attempt at a Solution I'm really rather confused by this problem...

Exactly, lol...I mean, I would think maybe if you cut the potential in half then solve for q then q1 and q2 would be equal? But that doesn't seem right at all... I'm a bit confused. How would I go about doing it?

Homework Statement "Two point charges 2.0cm apart have an electric potential energy -180 microJoules. The total charge is 31 nC. What are the two charges?" Homework Equations V= k * q / r The Attempt at a Solution I understand that V = -180 * 10^-6, k = 9*10^9, r = 0.02m, and the...

You're absolutely right :D Got it, ty!

The potential difference necessary to accelerate an He+ ion...? Homework Statement "What potential difference is needed to accelerate a He+ ion (charge +e, mass 4u) from rest to a speed of 1.2×10^6 m/s?" Homework Equations K_f + q*V_f = K_i + q*V_iThe Attempt at a Solution I figure that...

D'oh! That was it! Hahah - thanks much, and sorry for the confusion :) You just allowed me to pass this assignment ^.^

Homework Statement Two circular disks spaced 0.50 mm apart from a parallel-plate capacitor. Transferring 1.90 x 10^9 electrons from one disk to the other causes the electric field strength to be 1.90 x 10^5 N/C. What are the diameters of the disks (in cm)? Homework Equations E = Q /...