Two circular discs spaced apart from a parallel plate capacitor ?

AI Thread Summary
The discussion revolves around calculating the diameter of circular disks in a parallel-plate capacitor based on the transfer of electrons and the resulting electric field strength. The user initially applied the formula E = Q / (ε₀ * A) but encountered errors in their calculations, particularly regarding the charge and area. Feedback highlighted confusion in the arithmetic and the incorrect relationship between the radius and diameter. Ultimately, the user corrected their mistakes, leading to a successful resolution of the assignment. The exchange emphasizes the importance of clear calculations and understanding of fundamental equations in physics.
Netsurfer733
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Homework Statement



Two circular disks spaced 0.50 mm apart from a parallel-plate capacitor. Transferring 1.90 x 10^9 electrons from one disk to the other causes the electric field strength to be 1.90 x 10^5 N/C. What are the diameters of the disks (in cm)?


Homework Equations



E = Q / (e_o * A)
A = [pie]*r^2

The Attempt at a Solution



I though I went through the right process for this, but maybe I'm not using the right equations somehow? Here's what I did:

E = Q / (e_o * A) ==> Q = (8.85*10^-12 C^2 / N*m^2) * A * (1.9*10^5 N/C) = 3.04 * 10^-1

A = [Pie]*r^2 ==> 1.81 * 10^-4 = [pie]*r^2 ==> r = 0.00759 and thusly D = 0.1517m which is equal to 15.2 cm. This turned out to be wrong.

Where did I mess up?
 
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Your derivation is a bit confusing; you seem to be mixing in pre-calculated values without showing how you got them. For example, I assume that the value "3.04 * 10^-1" is supposed to be the charge due to the moved electrons. The mantissa looks okay, but the power of ten is way off. Perhaps your value for A is off because of that.
 
well, the first thing i see is that your diameter is more than twice your radius.

the first line of your solution is confusing; it looks like you are doing many steps at once and i am not sure what the last number is supposed to be since there are no units (if it is supposed to be the charge, it seems too big).

the reasoning is correct as far as i can tell, but you need to check your arithmetic and the value of the charge.
 
eczeno said:
well, the first thing i see is that your diameter is more than twice your radius.


D'oh! That was it! Hahah - thanks much, and sorry for the confusion :) You just allowed me to pass this assignment ^.^
 
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