Recent content by neurospade

Figured it out! Neglected the fact that alpha = a_t / R -- once I realized that I was able to use the equations. Got theta final = 10.987 rad, comes out to 1.75 revolutions. Thanks for the help!

Fnet_r = m*omega^2*r 50 = .5 * omega^2 * 1.2 omega = 9.13 rad/s Fnet_t = m*a_t 2.27 (Thrust minus frictional force) = 0.5 * a_t a_t = 4.54 m/s^2 Not sure where to go from here...

Ok, so if the initial angular velocity is 0 and the final angular velocity is 9.125 rad/s, how can I calculate theta from the kinematics equations? With Theta_initial = 0 rad. The free body diagram I described above is the free body diagram I have for the block in motion. Am I missing something?

I thought I solved for the *initial* angular velocity. For the free-body diagram I have the tension force (not sure of the value of it), the frictional force, the thrust force, and then the normal force and gravity (which should cancel out). Am I missing something?

Homework Statement A .5 kg steel block rotates on a steel table, attached to a 1.20m-long hollow tube. Air is fed through the tube and is ejected from the block, giving it a thrust force of 5.21N perpendicular to the tube. Max tension the tube can withstand without breaking is 50N. Assume...