Recent content by nevada2012

ok i figure out the first step. all that they did was converted from moles to g to kg then multiply the specific heat then convert to J then to KJ then to C and then to K now i am confuse as to how they found the P i understand that the equation is pv=nrt which becomes p=nrt/v but...

i don’t understand how they got this answer can you please explain the steps needed to fine the Final T and How the final P was found. thanks N2H4 + 3O2 ==> 2NO2 + 2H2O assume there are 60 moles of O2, what is the final T and P V = 20L T1 = 290K n (N2H4) = 20 Cp = 57 kJ/C...

hey guys i am having a really hard time doing enthalpy problems, i am trying to do this(its not an homework question) Calculate the enthalpy of formation of ethane (C2H6) given that the enthalpy of combustion of ethane is -2840kj. DeltaHfH2O(1) = -286 kg/mol Delta HfCO2 (g) =-394...