ok i figure out the first step.
all that they did was converted from
moles to g to kg then multiply the specific heat then convert to J then to KJ then to C and then to K
now i am confuse as to how they found the P
i understand that the equation is pv=nrt which becomes p=nrt/v
but...
i don’t understand how they got this answer
can you please explain the steps
needed to fine the Final T and How the final P was found.
thanks
N2H4 + 3O2 ==> 2NO2 + 2H2O
assume there are 60 moles of O2, what is the final T and P
V = 20L
T1 = 290K
n (N2H4) = 20
Cp = 57 kJ/C...
hey guys i am having a really hard time doing enthalpy problems,
i am trying to do this(its not an homework question)
Calculate the enthalpy of formation of ethane (C2H6) given that the enthalpy of combustion of ethane is
-2840kj. DeltaHfH2O(1) = -286 kg/mol Delta HfCO2 (g) =-394...